Math, asked by sainidee1590, 1 year ago

there is a slide in a park one of its side walls is painted red with the message dogs are not allowed in the park if the side of the wall are 6m,8m and 10 M find the cost of painting in red at the rate of 10 rupees per metre

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Answered by Anonymous
1
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Answered by Anonymous
16

\huge\mathfrak\blue{\underline{\underline{Solution :-}}}

For finding area of the wall, we have

2s = Perimeter of the wall = AB + BC + CA, where c = AB, a = BC and b = CA.

2s = 8m + 10m + 6m

2s = 24m

s = 12m.

Then, area of a triangular wall ABC,

\implies \sf\sqrt{(s-a)(s-b)(s-c)}

\implies \sf\sqrt{12(12-10)(12-6)(12-8)m^2}

, where a = 10m , b = 6m and c = 8m.

\implies \sf\sqrt{12×2×6×4m^2}

\implies \sf\sqrt{6×2×2×6×4 m^2}

\implies\sf{(6×2×2)} \sf{m}^{2}

24 m².

So, the cost of painting in red at the rate of 10 per .

= 10 × 24

\huge\red{\boxed{\boxed{Rs.240}}}

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