Math, asked by rsahni, 1 year ago

there is a slide in park. one of its side walls has been painted in some colour with a message "KEEP THE PARK GREEN AND CLEAN". if the sides of the wall are 15m, 11m and 6m, find the area painted in colour.

Please help me out with this guys please

Answers

Answered by KoenaMishra
3
area =
 \sqrt{s(s  - a)(s - b)(s - c)}
where s= perimeter ÷2
perimeter = 15+ 11+6= 32m
s = 16 m
 \sqrt{ 16(16 - 11)(16 - 5)(16 - 15)}
 \sqrt{ 16(16 - 11)(16 - 5)(16 - 15)}
 \sqrt{ 4 \times  4 \times 5 \times 11 \times 1}

=
4 \sqrt{55}
Answered by Agamsain
18

Answer :-

  • Area if painted wall = 20√2 cm²

Given :-

  • Length of first side = 15 metres
  • Length of second side = 11 metres
  • Length of third side = 6 metres

To Find :-

  • The area of Painted wall.

Explanation :-

As we know, by using Heron's Formulae we need semi-perimeter of triangle or triangular object.

Finding Semi-perimeter of wall

\implies \rm \dfrac{Side \: 1 + Side \: 2 + Side \: 3}{2}

\implies \rm \dfrac{15 + 11 + 6}{2}

\implies \rm \dfrac{32}{2}

\boxed { \implies \rm \bold { 16 \: cm}}

Now, Substituting the values

\implies \rm \sqrt{s (s - a) (s - b) (s - c)}

\rm \implies \sqrt{16 (16 - 15) (16 - 11) (16 - 6)}

\implies \rm \sqrt{16 (1) (5) (10)}

\implies \rm \sqrt{16 \times 1 \times 5 \times 10}

\implies \rm \sqrt{800}

\underline { \boxed { \implies \rm \bold { 20 \sqrt{2} \: cm^2 }}}

Hence, the area of painted wall is 20√2 cm²

@Agamsain

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