Question

there is a slide in park. one side walls has been painted in some colour with a message KEEP THR PARK GREEN AND CLEAN. if the sides of the walls are 15m, 11m , 6m, find the area painted in a colour. please answer fast.​

Answer 1

Answer:

The perimeter of a triangle is equal to the sum of its three sides it is denoted by 2S.

2s=(a+b+c)

s=(a+b+c)/2

Here ,s is called semi perimeter of a triangle.

The formula given by Heron about the area of a triangle is known as Heron's formula.

According to this formula area of a triangle= √s (s-a) (s-b) (s-c)

Where a, b and c are three sides of a triangle and s is a semi perimeter.

This formula can be used for any triangle to calculate its area and it is very useful when it is not possible to find the height of the triangle easily .

Heron's formula is generally used for calculating area of scalene triangle.

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Solution:

Here area painted in colour will be equal to the area of triangle with side 15m,11m and 6 m

Let the Sides of the triangular wall are a=15 m, b=11 m & c=6 m.

Semi Perimeter of the ∆,s = (a+b+c) /2

Semi perimeter of triangular wall (s) = (15 + 11 + 6)/2 m = 16 m

Using heron’s formula,

Area of the wall = √s (s-a) (s-b) (s-c)

= √16(16 – 15) (16 – 11) (16 – 6)

= √16 × 1 × 5 × 10

= √ 4×4×5×5×2

= 4×5√2

= 20√2 m²

Hence, the area painted in colour is 20√2 m².

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hope it helps you

pls mark as brainliest

Answer 2

Answer :-

• Area if painted wall = 20√2 cm²

Given :-

• Length of first side = 15 metres
• Length of second side = 11 metres
• Length of third side = 6 metres

To Find :-

• The area of Painted wall.

Explanation :-

As we know, by using Heron's Formulae we need semi-perimeter of triangle or triangular object.

Finding Semi-perimeter of wall

$\implies \rm \dfrac{Side \: 1 + Side \: 2 + Side \: 3}{2}$

$\implies \rm \dfrac{15 + 11 + 6}{2}$

$\implies \rm \dfrac{32}{2}$

$\green { \boxed { \implies \rm \bold { 16 \: cm}}}$

Now, Substituting the values

$\implies \rm \sqrt{s (s - a) (s - b) (s - c)}$

$\implies \rm \sqrt{16 (16 - 15) (16 - 11) (16 - 6)}$

$\implies \rm \sqrt{16 (1) (5) (10)}$

$\implies \rm \sqrt{16 \times 1 \times 5 \times 10}$

$\implies \rm \sqrt{800}$

$\red { \underline { \boxed { \implies \rm { \bold { 20 \sqrt{2} \: cm^2 }}}}}</p><p>$

Hence, the area of painted wall is 20√2 cm²

@Agamsain