Question

There is a solid cylinder of a right circular cylinder with a hemisphere at one end and a cone at other side . Their common radius is 7cm . The height of the cylinder and cone are each of 4cm . Find volume of solid

Answer 1

$<b><i>$

$<u>Answer:</u>$

The total surface area of the solid is 373.45 cm²

Step-by-step explanation:

Given :  

Height of the conical part  (h) = 6 cm

Height of the cylindrical part , H = 10 cm

Radius of the cone & cylinder, (r) = 3.5 cm                  

Let, ‘l’ be the slant height of cone.

l = √r² + h²

l = √3.5² + 6² = √12.25 + 36 = √48.25  

l = √48.25

l = 6.95 cm

Slant height of the cone (l) = 6.95 cm

Curved surface area of the cone (S1) = πrl

S1 = 22/7 × (3.5)(6.95) = 22 × 0.5 × 6.95

S1 = 76.45 cm²

Curved surface area of the cylinder  (S2) = 2πrH  

S2 = 2 × 22/7 × 3.5 × 10

= 2 × 22 × 0.5 × 10 = 44 × 5  

S2 = 220 cm²

Curved surface area of the cylinder  (S3) = 2πr²

S3 = 2 × 22/7 × 3.5² = 2 × 22/7 × 3.5 × 3.5

= 2 × 22 × 0.5 × 3.5 = 44 × 1.75 = 77 cm²

S3 = 77 cm²

Total surface area of solid  (S) = S1 + S2 + S3

S = 76.45 + 220 + 77  

S = 373.45 cm²  

Hence, the total surface area of the solid is 373.45 cm² .

HOPE THIS ANSWER WILL HELP YOU...