Question

There is a spinner with 13 equal areas, numbered 1 through 13. If the spinner is spun one time, what is the probability that the result is a multiple of 4 or a multiple of 3?

Answer 1

Given :- There is a spinner with 13 equal areas, numbered 1 through 13. If the spinner is spun one time, what is the probability that the result is a multiple of 4 or a multiple of 3 ?

Answer :-

we have,

→ Total number of outcomes = 1 to 13 = 13

now,

→ Multiple of 4 upto 13 = 4, 8 and 12,

→ Multiple of 3 upto 13 = 3, 6 , 9 and 12 .

so,

→ Multiple of 4 or 3 = Total favourable outcomes = 3 + 4 = 7 .

then,

→ Required probability = Total favourable outcomes / Total number of outcomes = (7/13) (Ans.)

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