Question

there is a square field of side am 10 metres in front of a house if a man covers this path in 40 seconds what will be the magnitude of the displacement of the men after 2 minutes 20 seconds​

Answer 1

Answer:

10 m is the displacement.

Answer 2

Answer:

14.14 m

Explanation:

Given side of square = 10m

Perimeter P = 40m

Time taken to cover the boundary of 40 m = 40 s

In 1 second, the man covers a distance of 1 m

Now distance covered by the man in 2 min 20 seconds = 1 × 140 = 140 m

Now the total number of rotation the man makes to cover a distance of 140 meters = perimeter /totaldistance = 3.5

At this point, the farmer is at a point say B from the origin O

Thus the displacement ( s ) = √10² + 10²

from Pythagoras theorem,

s = 10 √2

=14.14m