Question

There is a square park of side 30cm and a rectangular park of length 7.3cm

and breadth 5.8cm. Which has larger area?​

Answer 1

Answer:

Perimeter of the rectangle = PQ + QR + RS + SP

= b +l + b + l

= 2b +2l

Again,

ABCD is a rectangle. We know that the opposite sides of a rectangle are equal.

Perimeter of a Rectangle

AB = CD = 5 cm and BC = AD = 3 cm

So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm

It can be written as 5 cm + 5 cm + 3 cm + 3 cm

= (2 × 5) cm + (2 × 3) cm

= 2 (5 + 3) cm

= 2 × 8 cm

= 16 cm

We add length and breadth twice to find the perimeter of a rectangle.

Perimeter of a rectangle = 2 (length + breadth)

Answer 2

Answer:

The area of square park is greater that the area of rectangular park.

Step-by-step explanation:

First, we find area of square park.

Side: 30 cm

Using the formula , we find the area : s*s = 30*30 = 900 sq.cm

Next, find the area of rectangular park

Length: 7.3 cm

Breadth: 5.8 cm

Using the formula , we find the area : l*b = 7.3*5.8 = 42.34 sq.cm

900 > 42.34

Thus, the area of square park is greater that the area of rectangular park.

Hope it helps :)