There is a square park of side 30cm and a rectangular park of length 7.3cm
and breadth 5.8cm. Which has larger area?
Answers
Answer:
Perimeter of the rectangle = PQ + QR + RS + SP
= b +l + b + l
= 2b +2l
Again,
ABCD is a rectangle. We know that the opposite sides of a rectangle are equal.
Perimeter of a Rectangle
AB = CD = 5 cm and BC = AD = 3 cm
So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm
It can be written as 5 cm + 5 cm + 3 cm + 3 cm
= (2 × 5) cm + (2 × 3) cm
= 2 (5 + 3) cm
= 2 × 8 cm
= 16 cm
We add length and breadth twice to find the perimeter of a rectangle.
Perimeter of a rectangle = 2 (length + breadth)
Answer:
The area of square park is greater that the area of rectangular park.
Step-by-step explanation:
First, we find area of square park.
Side: 30 cm
Using the formula , we find the area : s*s = 30*30 = 900 sq.cm
Next, find the area of rectangular park
Length: 7.3 cm
Breadth: 5.8 cm
Using the formula , we find the area : l*b = 7.3*5.8 = 42.34 sq.cm
900 > 42.34
Thus, the area of square park is greater that the area of rectangular park.
Hope it helps :)