Question

There________is a table and two chairs in 1 point ________class.​

Answer 1

Answer:

Solution

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Let the cost of one table =x

And cost of one chair =y

⇒4x+3y=2250

⇒3x+4y=1950

Equation (1) × 3 : 12x+9y=2250×3

Equation (2) × 4 : 12x+16y=1950×4

Subtract two equations ;

⇒7y=1050

⇒y=150

⇒x=450

⇒cost of one table =x=450

⇒cost of one chair =y=150

⇒cost of 2 chairs and 1 table =2x+y=2(450)+150=1050

Explanation:

Answer 2

Answer:

Explanation:

There is a table and two chairs in 1 point of class