there is a temperature it is numerically the same in both Fahrenheit and Celsius? if yes ,
find it
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temp in C = (C -0)/100
temp in F = (F - 32)/180
Let the temperature be x.
temp in C = temp in F
(x-0)/100 = (x-32)/180
⇒180x = 100x -3200
⇒80x = -3200
⇒x = - 3200/80 = -40
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