There is a trapezium whose parallel sides are 10 cm and 22.3 CM the distance between the parallel sides is 3.7 CM. Then, we have a rhombus with diagonals 41.8 cm and 0.03 M find which figure has greater area and by how much?
Answers
Area of rhombus > Area of Trapezium & Rhombus has greater area by 2.945 cm²
Step-by-step explanation:
a trapezium whose parallel sides are 10 cm and 22.3 CM the distance between the parallel sides is 3.7 CM
Area of Trapezium = (1/2)(10 + 22.3) * 3.7
= (1/2) 32.3 * 3.7
= 59.755 cm²
a rhombus with diagonals 41.8 cm and 0.03 m
1 m = 100 cm
0.03 m = 3 cm
Area of rhombus = (1/2) * d1 * d2
= (1/2) * 41.8 * 3
= 62.7 cm²
62.7 > 59.755
Area of rhombus > Area of Trapezium
62.7 - 59.755 = 2.945 cm²
Rhombus has greater area by 2.945 cm²
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