there is a trapezium whose parallel sides are 10 cm and 22.3 CM the distance between the parallel sides is 3.7 CM then we have a rhombus with a diagonal is 41 point 8 cm and 0.0 3 m find which figure has greater area and by how much
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the area of trapezium is 1/2×(22.3+10)×3.7
=59.755 cm^2
area of Rhombus is 1/2×41.8×3
=62.7 cm^2
so the Rhombus has greater area than trapezium by 2.945 cm^2.
=59.755 cm^2
area of Rhombus is 1/2×41.8×3
=62.7 cm^2
so the Rhombus has greater area than trapezium by 2.945 cm^2.
rahul147637:
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