Question

there is a triangle party plot with the length of the sides 200 m, 210m, and 290 m. Find the cost of raising the lawn in that plot at rate of ruppes 5/m²​

Answer 1

Answer:

Area of ∆ = 1/2 * 200 * 210 ( since ∆ is right angled ∆ )

cost of raising = 100*210*5 = 105000 (Ans)

Answer 2

The cost of raising the lawn in that plot at the rate of Rs 5/m²​ is Rs 1,05,000.

Step-by-step explanation:

We are given that there is a triangle party plot with the length of the sides 200 m, 210 m, and 290 m.

As we know that the Pythagoras theorem states that;

$\text{Hypotenuse}^{2} = \text{Perpendicular}^{2} + \text{Base}^{2}$

So, in our triangle; if we assume that Hypotenuse = 290 m, Perpendicular = 210 m and Base = 200, then the above condition is satisfied, i.e;

$290^{2} = 210^{2} + 200^{2}$

84100 = 44100 + 40000

84100 = 84100

This means that the given triangle is a right-angled triangle having base = 200 m and height (altitude) = 210 m

Now, the area of the triangle =  $\frac{1}{2}\times \text{Base} \times {\text{Height}}$

                                                =  $\frac{1}{2}\times 200 \times 210$

                                                =  21,000 $\text{m}^{2}$

Now, the cost of raising the lawn in the plot of 1 $\text{m}^{2}$ = Rs 5

so, the cost of raising the lawn in the plot of 21,000 $\text{m}^{2}$ = Rs (21,000 $\times$ 5)

                                                                                            = Rs 1,05,000