Question

There is a triangular park ABC whose two corner angles A and B are 50 and 60"
respectively. Three friends Rashmi, Sita and Geeta go daily for a morning walk along
these three sides AB, BC and AC respectively. Who walks maximum distance among these three? Who walks least?

Answer 1

Step-by-step explanation:

mxp_ykrx_nhe come here 9th 10th girls for repro.duction cha.pter

Answer 2

In triangle ABC,

angle A = 50 degree , angle B = 60 degree , angle C = x degree  

- Sum of the angles of a triangle = 180 degree

    50 + 60 + x = 180

110 + x = 180   so   angle C = 180 - 110          

∴ angle C = 70 degree

And the side AB is opposite to angle C which is the maximum angle amongst other two angles  

So, Rashmi walks the maximum distance that is AB.

Sita walks BC which is opposite to smallest angle A = 50° means Sita walks minimum distance of triangular ABC :)

i hope this helped ya buddy :) tpwk <3