Question

there is a Triangular Park pqr in a Colony husainganj PQ and are in the ratio 2:5:3 respectively. It was observed that three freinds A, B and C go daily for morning walk in this Park and walk along three sides PQ, QRand PR respectively of this park
1) walks minimum distance
2)walks maximum distance​

Answer 1

Answer:

1) A walks minimum distance.

2) B walks maximum distance.

Step-by-step explanation:

As given,

In the ratio, 2:5:3

Sides PQ, QR and PR

Therefore, QR is the longest side.

and, PQ is the shortest side.

So, the person who walks on the longest side walks maximum distance.

And the one who walks the shortest, walks the minimum distance.

So, B walks maximum and A walks minimum distance.

Hope you get this!!