There is a triangular park with sides 7 m, 8m and 5 m. Taking Park as ABC, AD is
perpendicular on BC. If trees are planted at A, B, C and D. Find the distance between
trees at A and D
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Answer:
Now , perpendicular line dropped from A would actually be the median of the given triangle ABC and would bisect BC
Step-by-step explanation:
Now length of BC=5cm
so half of BC =5/2=2.5cm
Now, BD=2.5cm and AB=7cm so, use pythagoras theorem over here,
Therefore, (AB)²=(AD)²+(BD)²
Now, 49-6.25=AD²
so, 42.75=AD², so
AD= 3/2×19^1/2
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