Question

There is a tunnel connecting city a &

b. There is a cat which is standing at 3/8 thelength of the tunnel from

a. It listens a whistle of the train and starts running towards the entrance where, the train and the cat meet. In another case, the cat started running towards the exit and the train again met the cat at the exit. What is the ratio of their speeds?

Answer 1

Answer:

the ratio of their speeds = 4 : 1

Explanation:

Let say Length of Tunnel = 8L

cat which is standing at 3/8 the length of the tunnel from a.

=> Distance from a (3/8)8L = 3L

Distance From b = 8L - 3L = 5L

& Speed of Train = T km /hr

Speed of Cat = C km/Hr

Distance Covered by CAT = 3L

Time Taken by Cat = 3L/C

Distance Covered by Train = T3L/C

in Case 2

Distance Covered by CAT = 5L

Time Taken by Cat = 5L/C

Distance Covered by Train = T5L/C  

Distance Covered by Train  is now Distance covered by Train Earlier + Tunnel Length

=> T5L/C  = T3L/C  + 8L

=> 5TL  = 3TL  + 8LC

=> 5T = 3T + 8C

=> 2T = 8C

=>T = 4C

=> T/C  = 4/1

the ratio of their speeds = 4 : 1