Question

There is a two digit number where the sum of the digits is 7. The actual value of the number is such that it equals 12 times the first digit minus 2. What is the number?

Answer 1

let the digit of a two digit number be x and y

x+y=7

y=7-x

so, the number is 10x+7-x

10x+7-x=12x-2

7+2=12x-10x+x

9=3x

3x=9

x=3

So the number will be,

10x+7-x=10*3+7-3

=34

Hope it helps.....