Question

There is a two digit number, whose tens is 3 times its ones digit. If its digits are reversed this new number is added to to 36, find the original number

Answer 1

SOLUTION:-

Given:

•There is a two digits number. whose tens is 3 times its ones digit.

•If its digits are reversed this new number is added to 36.

To find:

The original number.

Explanation:

•Assume the digit at unit's place be R.

•Digit in ten's place be 3R.

So,

Original number: 10(3R) + R

Reversed number: 10(R) +3R

If the digits are reversed this new number is added to 36.

According to the question:

=) 10(3R)+R= 10(R) + 3R+36

=) 30R +R = 10R +3R+36

=) 31R = 13R+36

=) 31R -13R = 36

=) 18R =36

=) R= 36/18

=) R= 2

Now,

Original number:

=) 10(3R) +R

=) 10(3×2) +(2)

=) 10(6) + 2

=) 60 +2

=) 62

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