There is a two digit whose unit digit was square a 3 and ten's digit was square of 2. then find the square root of that number?
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This question is not meaning full
This question is not meaning full
This question is not meaning full
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First we find the square of 3 which is nothing but 9
Then we also find the square of the ten's digit no.- two square which is 4.
Therefore we get 49. It's square root is 7
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