Question

There is a uniform electric field in x-direction. If the work done by external agent in moving a charge of 0.2 c through a distance of 2 metre slowly along the line making an angle of 60 with x-direction is 4 joule, then the magnitude of e

Answer 1

Charge (q) = 0.2 C; Distance (d) = 2m; Angle

q = 60° and work done (W) = 4J.

Work done in moving the charge (W)

E = W\qdcos = 4\0.4*0.5

E = 20N\C

Answer 2

Answer:

The electric field will be 20 N/C.

Explanation:

Given that,

Charge q = 0.2 C

Distance d = 2 m

Angle = 60°

Work done W = 4 J

We know that,

The relation between the electric field and work done is defined as:

$E = \dfrac{W}{q\ d\ cos\ \theta}$

Where, E = electric field

W = work done

Q = charge

d = distance

We substitute the value in to the formula

$E= \dfrac{4}{0.2\times2\times\ cos\ 60^{\circ}}$

$E=\dfrac{4}{0.2\times2\times0.5}$

$E = 20\ \dfrac{N}{C}$

Hence, The electric field will be 20 N/C.