Question

there is a uniform electric field of strength 10*3 v/m along y axis​

Answer 1

Solution :

Body moves along the parabolic path. For vertical motion : By using v = u + at Þ vy=0+QEm.t=10−6×10310−3×10=10m/sec For horizontal motion ? It?s horizontal velocity remains the same i.e. after 10 sec, horizontal velocity of body vx = 10 m/sec. Velocity after 10 sec v=v2x+v2y−−−−−−√=102√m/sec

Answer 2

e field is long y axis

therefore potential drop will only be along y axis

along axis potential is constant

there gain in kinetic energy = loss in potentail energy

loss in p.e =0

gain in k.e = 0

velocity remains same