Question

There is a wire of length 20 cm and having resistance 20 OHM cut into 4 equal pieces and then joined in series. The equivalent resistance is​

Answer 1

Explanation:

Given There is a wire of length 20 cm and having resistance 20 OHM cut into 4 equal pieces and then joined in series. The equivalent resistance is

• The new resistance will be half of its original resistance when any resistor is cut into two equal parts
• So R1 = R2 = R3 = R4 = 20 / 4 = 5 ohms
• Now resistors are connected in series and so the equivalent resistance will be
• R = R1 + R2 + R3 + R4
•     = 5 + 5 + 5 + 5
•     = 20 ohms

Reference link will be

https://brainly.in/question/37882943

Answer 2

Answer:

20 ohm

Explanation:

GIVEN:

Original Wire:

1. length (l) = 20 cm
2. resistance (R) = 20 Ω

New Wire:

1. length (l) = 20/4 = 5 cm

Since Length ∝ Resistance

2. resistance (R) = 20/4 = 5 Ω

TO FIND: Equivalent resistance R(series)

SOLUTION:

R(s) = R×n

= 5×4

= 20 Ω