There is an auditorium with 27 rows of seats. There are 20 seats in the first row, 22 seats in the second row, 24 seats in the third row and so on. Find the number of seats in the 15th row and also find how many total seats are there in the auditorium? Solve the word problem
Answers
Answered by
6
Step-by-step explanation:
Number of seats in 15th row:
n=15, a=20, d=2,
a+(n-1)d
20+(15-1)2=48
Total seats are there in the auditorium:
n=27, a=20, d=2,
n/2[2a+(n-1)d]
27/2[40+(27-1)2]=1242
Answered by
4
Answer:
number of seats in the 15th row = 48
total seats in the auditorium = 1242
Step-by-step explanation:
20 seats in the first row
22 seats in the second row
24 seats in the third row & so on
Hence This is an AP
where
a = First Term = 20 = seat in 1st row
d = Common difference = 22 - 20 = 2
n = 27 = number of Rows
Number of Seats in 15th row
= a + 14d
= 20 + 14*2
= 48
number of seats in the 15th row = 48
Total Seat
Sum = (n/2)(2a + (n-1)d)
= (27/2)(2*20 + (26)*2)
= 27 * 46
= 1242
total seats in the auditorium = 1242
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