Question

There is an Electric field E in x-direction. If the work done in moving a charge of 0.2 C through a distance of 2m along a line making angle 60o with x-axis is 4 J, then what is the value of E?

Answer 1

Answer:

W = FsCos60

or, 4 = 2F/2

or, F = 4 N

or, qE = 4

or, E = 4÷0.2 = 20 N/C(Answer)

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Answer 2

Answer:

Explanation:

Electric field is along X-axis and charge is moved along the direction makings angle of 60o with positive X-axis there fore Electric filed along given direction will be Ecos60

Work done in the given direction W=Force × displacement

Work done in the given direction W=(qEcos60 )× d

4=[(0.2)E (1/2)]×(2)

On simplification we get E=20 N/C