There is an equiconvex glass lens with radius of each face as R and = 3/2 and
au = 4/3. If there is water in object space and air in image space, then the focal length is
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the right answer will be 3R/2...
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The focal length is 3R/2
Given-
- Radius of each face = R
- μg = 3/2
- μw = 4/3
Focal length can be given by -
1/f = (μ-1) (1/R₁ - 1/R₂)
where f is focal length, μ is refractive index and R is radius of curvature.
1/f = n₂ - n₁/R₁ + n₃ - n₂/R₂
By substituting the values we get
1/f = 3/2-4/3 / R + (1 - 3/2) / -R
f = 3R/2
Refer to the attached image for more details.
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