There is an equilateral triangle in the XY plane with its centre at the origin. The distance of its vertices from the origin is 3.5 cm. The area of its circumcircle in cm 2 is 5 points
Answers
Given:
There is an equilateral triangle in the XY plane with its centre at the origin. The distance of its vertices from the origin is 3.5 cm.
To find:
The area of its circumcircle in cm 2 is
Solution:
From given, we have,
The distance of its vertices from the origin is 3.5 cm
Consider the attached figure while going through the following steps.
From the figure, it's clear that the distance of its vertices from the origin is equal to the radius of the circumcircle.
Therefore, the area of its circumcircle = πr²
given, r = 3.5 cm, we have,
The area of its circumcircle = π (3.5)²
= 22/7 × (3.5)²
= 38.5 cm²
∴ The area of its circumcircle in cm 2 is 38.5 cm²
Answer:
The area of its circumcircle in cm 2 is 38.5cm²
Step-by-step explanation:
Given:
There is an equilateral triangle in the XY plane with the center. The distance from its peaks to the source is 3.5 cm.
Search:
The space around its perimeter is 2 cm
Solution:
Since the evening we have
The distance from its peaks to the source is 3.5 cm
Consider the attached number as you go through the following steps.
It is clear from the number that the distance from its initial vertices is equal to the radius of the circle.
The area around it is therefore = πr²
evening, r = 3,5 cm, we have,
Its perimeter area = π (3,5) ²
= 22/7 × (3.5)
= 38.5 cm²
∴ Its circumferential area in cm 2 is 38.5 cm².
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