Question

there is an error of 3% of side of a square the error in area​

Answer 1

Answer:

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Explanation:

We assume that the side of the square is measured 3% in excess.

Lets assume side is 100 cm

100 cm is read as 103 cm.

A1 = (100 x 100) cm² and

A2 = (103 x 103) cm².

Difference in Area:

(A2² - A1²) = [(103)² - (100)²]

= (103 + 100) x (103 - 100)

= 203*3

= 609

Percentage error = (609x100)/(100*100) = 6.09%