There is an ester{ C3H7COOHC2H5} FIND what type of acid or alcohol be used
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Answer:TO FORM AN ESTER C3H7COOHC2H5 PROPANOIC ACID AND PROPANOL ALCOHOL SHOULD BE USED .
Explanation: AS NO OF CARBON IN ESTER IS 6
6/2=3
THEREFORE 3RD MEMBER OF CARBOXYLIC ACID AND ALCOHOL
FAMILY SHOULD BE USED.
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