Question

there is an explosion on the surface of a lack and two people Phuntsho and Nado here it's sound. Phuntsho is 150m away from a boat and Nado is 150m below the surface of water.who would hear the sound first and why?​

Answer 1

Answer:

Explanation:

speed of sound in air = 344 m/s

distance covered = 100 m

time taken by sound = t sec

velocity = distance / time

 

 344 = 100 / t

 t  = 100 / 344

 t = 0.29 sec

 

Now, for the man below the surface of water

speed of sound in water = 1533 m/s

distance covered = 100 m

time taken = t

But velocity = distance / time

     1533 = 100 / t

        t   = 100 / 1533 

         t  = 0.06 sec

So , the man under the water hear the sound of the explosion first....