Question

there is an imaginary planet whose mass is three times that of the earth and radius is one third times of calculating the acceleration due to gravity on that planet take g on earth=m/s^2​

Answer 1

Answer:

Given that,

Mass of the earth =M

Radius of the earth = R

We know that,

g=

R

2

GM

Now, mass and radius is double

g

′

=

4R

2

G2M

g

′

=

2R

2

GM

g

′

=

2

1

g

Hence, the acceleration due to gravity on the surface of a planet is

2

1

g