there is an object infront of convex mirror at the distance of 5cm.if it's focal lenth is 10cm then find magnification and image diatance
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Answer:
u = -5cm, f = 10cm
We know that
1/v + 1/u = 1/f
⇒ 1/v + 1/-5 = 1/10
⇒ 1/v = 1/10 + 1/5 = 3/10
∴ v = (10/3)cm = 3.33 cm
The position of the image is 3.33 cm behind the convex mirror.
Magnification, m = -v/u = -3.33/-5 = 0.66
The image is virtual and erect.
HOPE IT HELPS YOU!!
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