there is circle with diameter 4cm and an angle PRO = 35° we need to find angle ROQ
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Hii
Angle ORQ=90-35=55
OR =OP=radius
Then angleOPR=55=angleROQ (by the property of isosceles triangle)
Then
180=55+55+anglePOR
180-110=angleROQ
70°=angleROQ
Angle ORQ=90-35=55
OR =OP=radius
Then angleOPR=55=angleROQ (by the property of isosceles triangle)
Then
180=55+55+anglePOR
180-110=angleROQ
70°=angleROQ
Tyson1111:
I need to find angle ROQ
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