Math, asked by rakeshtiwari4465, 2 months ago

there is difference of 25 year between the age of father and his son after ten years son age will be half of his father's age find their present ages​

Answers

Answered by gurjotsingh66655
0

Answer:

15,40

Step-by-step explanation:

Step-by-step explanation:let present age of son be x

Step-by-step explanation:let present age of son be xtherefore present age of father is x+25

A.T.Q

A.T.Q x+10 = 1/2 (x+35)

A.T.Q x+10 = 1/2 (x+35) 2(x+10) =x+35

A.T.Q x+10 = 1/2 (x+35) 2(x+10) =x+35 2x+20 =x+35

A.T.Q x+10 = 1/2 (x+35) 2(x+10) =x+35 2x+20 =x+35 2x-x =35 - 20

A.T.Q x+10 = 1/2 (x+35) 2(x+10) =x+35 2x+20 =x+35 2x-x =35 - 20 x = 15

A.T.Q x+10 = 1/2 (x+35) 2(x+10) =x+35 2x+20 =x+35 2x-x =35 - 20 x = 15 present age of son= x= 15

A.T.Q x+10 = 1/2 (x+35) 2(x+10) =x+35 2x+20 =x+35 2x-x =35 - 20 x = 15 present age of son= x= 15 present age of father = x+25= 15+25=40

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