Question

There is food provision for 100 men for 30 days. If the number of men is reduced to 80, then the number of days the food could last for is​

Answer 1

➜ ANSWER :•

" 37 DAYS "

➜ GIVEN :•

• Number Of Days = 30 days
• Number Of Men's = 100 men's

➜ REQUIRED :•

• Number of days when the number of mens is reduced to 80 = ???

➜ SOLUTION :•

• LET THE NUMBER OF DAYS IS X

NO. OF DAYS = NO. OF MENS

⇩ 30 = 100 ⇧

⇩ x = 80 ⇧

30 : x = 80 : 100

Product of Means = Products of Extremes

x × 80 = 30 × 100

80x = 3000

x = 3000 ÷ 80

x = 37

:• HENCE VERIFIED ; THAT THE FOOD PROVISION WILL LAST FOR 37 DAYS FOR THE 80 MENS .

➜ REMINDER :•

• IT'S AN INDIRECT QUESTION !

• In a Proportion , the second and the third elements are called "means of a proportion" and the first and the fourth elements are called " extremes of a proportion " while the product of mean proportion is always equal to the product of extreme .

════════ ❃ ═══════

~@amna3961 ☻♡

Answer 2

➜ ANSWER :•

" 37 DAYS "

➜ GIVEN :•

Number Of Days = 30 days

Number Of Men's = 100 men's

➜ REQUIRED :•

Number of days when the number of mens is reduced to 80 = ???

➜ SOLUTION :•

LET THE NUMBER OF DAYS IS X

NO. OF DAYS = NO. OF MENS

⇩ 30 = 100 ⇧

⇩ x = 80 ⇧

30 : x = 80 : 100

Product of Means = Products of Extremes

x × 80 = 30 × 100

80x = 3000

x = 3000 ÷ 80

x = 37

:• HENCE VERIFIED ; THAT THE FOOD PROVISION WILL LAST FOR 37 DAYS FOR THE 80 MENS .

➜ REMINDER :•

IT'S AN INDIRECT QUESTION !

In a Proportion , the second and the third elements are called "means of a proportion" and the first and the fourth elements are called " extremes of a proportion " while the product of mean proportion is always equal to the product of extreme .

════════ ❃ ═══════

~@omasati2004☻♡