Question

there is one and only one circle that can passing non-conical point? proof​

Answer 1

Answer:

The point O lies on the perpendicular bisector of AB. And also, O lies on the perpendicular bisector of BC. Thus, we can say from above OA = OB = OC = r (where r stands for radius of the circle). ... Hence, there is one and only one circle passing through three non collinear points that are A, B and C.