There is one odd integer N between 400 and 600 that is divisible by both 5 and 11. Find the sum of the digits of N.
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Answer:
Step-by-step explanation:
let N = 2p+1 be this number
400 < 2p+1 < 600
=> 399<2p+1<599
=> 398<= 2p <=598
=>199<=p<=299
2p+1 divisible by 5 =>
2p+1 = 5k
And 2p+1= 11m ( divisible by 11)
=>
2p+1 is divisinle by 55
The numbers divisible by 55 from
400 to 600 are .
0, 55 , 110, 165, 220. 275, 330, 385, 440 , 495, 550, 610
Three solutiond 440 , 495 , and 555
If we devide them by 55
E will get 8 9, and 10
The odd number is 495 only solution.
HOPE IT HELPS YOU.
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