There is Q-14 and Q-15
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14Given number of nitrogen atoms = 3.011 X 1023
Number of moles = Number of particles / Avogadro number
= 3.011 X 1023 / 6.023*1023
= 0.5 moles
So, Mass = moles * molar mass
= 0.5 * 14
= 7g
So, 7g is the mass of 3.011 X 1023 number of nitrogen atoms.
156.022 x 1023 molecules is present in nitrogen molecule
therefore it is equal to the mass of nitrogen molecule
= 28 gm
I hope this will help you
Number of moles = Number of particles / Avogadro number
= 3.011 X 1023 / 6.023*1023
= 0.5 moles
So, Mass = moles * molar mass
= 0.5 * 14
= 7g
So, 7g is the mass of 3.011 X 1023 number of nitrogen atoms.
156.022 x 1023 molecules is present in nitrogen molecule
therefore it is equal to the mass of nitrogen molecule
= 28 gm
I hope this will help you
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