Question

There is rectangle of Length 20cm. Its area is 200 sq.cm. Find its perimeter ​

Answer 1

Answer :

• Perimeter of rectangle is 60cm.

Given :

• Length of rectangle is 20cm
• Area is 200 cm²

To find :

• Perimeter of rectangle

Solution :

First we need to find the breadth of rectangle

Given

• Length of rectangle is 20cm
• Area is 200cm²

• Let the breadth of rectangle be b

We know that

• Area of rectangle = l × b

Where,

• l is length
• b is breadth

→ Area of rectangle = length × breadth

→ 200 = 20 × b

→ b = 200/20

→ b = 10

Breadth of rectangle is 10cm.

Finding the perimeter of rectangle :

• Length of rectangle is 20cm
• Breadth of rectangle is 10cm

We know that

• Perimeter of rectangle = 2(l + b)

Where,

• l is length of rectangle
• b is breadth of rectangle

→ Perimeter of rectangle = 2(l + b)

→ Perimeter of rectangle = 2(20 + 10)

→ Perimeter of rectangle = 2(30)

→ Perimeter of rectangle = 60cm

Hence , Perimeter of rectangle is 60cm.

Answer 2

Area of a rectangle is given to be 200 cm²

Also, the length of the rectangle is 20cm

We will first find the breadth of the rectangle

area of rectangle = length × breadth

200 = 20 × breadth

breadth = 200/20

= 10 cm

We have to find the perimeter of the rectangle

perimeter = 2( length + breadth)

= 2( 20 + 10 )

= 60 cm

Hence, the perimeter of the rectangle will be 60 cm