Question

There is some fire incident in the house. The fireman is trying to enter the house from the
window as the main door is locked. The window is 6 m above the ground. He places a
ladder against the wall such that its foot is at a distance of 2.5 m from the wall and its top
reaches the window.
att
і неге,
SPEL
be the
wall with the windows
be the ladder and
a, GA AB
b. AB AG
d AB, BC
IL We will apply Pythagoras Theorem co And length of the ladder. It is.
a. AB2 = BC2 - CAP
b. CA2- EC2# AB
CBC = ABR CAR
a AB2 = BC2 - GA2
iii. The length of the ladder is
a. 4.5 m
b! 2.5 m
c. 6.5 m
d. 5.5 m
iv. What would be the length or the ladder ir it is placed om away mom te wau and the
window is 8 m above the ground?
a. 12 m
b. 10 m
11m
d. 8 m
v. How far should the ladder be placed if the fireman gets a 9 m long ladder:
a. 6.7 m (approx.)
b. 7.7 m (approx.)
c. 5.7 m (approx.)
d. 4.7 m (approx.)​

Answer 1

Answer:

don't know so long to answer give one one question please