Math, asked by manojbhise4110, 10 months ago

There is some water in a tank. Water is then poured into the tank until the volume of water is 8 times as much as the initial volume of water in the tank. When another 16.75 liters of water is added, the total volume of water in the tank becomes 20.35 liters. How much water is in the tank at first? Give your answer in liters.

Answers

Answered by mhanifa
2

Answer:

0.45 liters

Step-by-step explanation:

Initial volume= x

- water added, volume becomes 8x

- water added 16.75 l, volume becomes 20.35 l

x->8x+16.75->20.35

  • 8x+16.75=20.35
  • 8x=20.35-16.75
  • 8x=3.6
  • x=3.6/8
  • x=0.45 l

Initial volume was 0.45 liters

Similar questions