There is something confusing with the question. look at the given image and try to find the answer.
AB=DC, DC=BC, ADC angle = 40, BCD angle = 140 Find ABC.
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BAD+∠BCD=180° (opposite angles of a cyclic quadrilateral are supplementary).
∴100°+∠BCD=180°∠BCD=80°
(ii) ∠ADC=∠BCD (Alt angles are equal)
∠ADC=80°
(iii) ∠ABC=∠BAD (Alt angles are equal)
∠ABC=100°
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