Math, asked by divya6632, 11 months ago

There is the option please give the answer step by step

Attachments:

Answers

Answered by october123
1

Answer

I think the answer what u have ticked is correct

Step-by-step explanation:

add -5/7 and 10/7 u get 5/7. keeping that in mind move forward...

add 1/12 and 3/4 ( 3/4 becomes 9/12 when multiplied with a common denominator that is 3 to make it even). so now u get 10/12 which can be simplified and be written as 5/6.moving on...

add -1/3 and -1/6 ( -1/3 becomes -2/6 when multiplied with a common denominator that is 2 to make it even). so now u get -3/6  which can be simplified and be written as -1/2.

now we have

5/7 + 5/6 + -1/2 = 5/7 + 2/6 (2/6 comes from adding 5/6 and -1/2)

2/6 when simplified gives 1/3

so, now we have to find a common denominator b/w 3 and 7 which is 21.

5/7 is nothing but 15/21 when multiplied with 3 ( to make the denominators common)

1/3 is nothing but 7/21 when multiplied with 3 ( to make the denominators common)

so,

                          = 15/21 + 7/21

                           =22/21 = 1 1/21

I hope this answer helps u...


divya6632: 15/21 where coming
october123: oh my bad I forgot to write that
october123: 2/6 when simplified gives 1/3
divya6632: please write
october123: I edited the answer
october123: here is ur new answer
divya6632: please show me the simplify
Answered by mkrishnan
0

Answer:

Step-by-step explanation:

-5/7 +1/12 +3/4+ [-1/3]+10/7 - 1/6 =   10/7 - 5/7  +3/4 +1/12  -1/3 -1/6

                                                     =10/7 - 5/7   +9/12 +1/12 - 4/12 - 2/12

                                                      =[10 -5]/7 + [9+1-4-2]/12

                                                       =5/7 +4/12

                                                       =5/7 + 1/3

                                                        =15/21 +7/21

                                                        =22/21

                                                        = 1  1/21

                                                   


divya6632: Thanks
mkrishnan: welcome
Similar questions