Question

There is three digit number,The second digit is six times as big as third digit while the first digit is four less than the second digit, What is the number?​

Answer 1

Answer:

261

Step-by-step explanation:

Last has to be 1 because second digit has to be 6 times last digit. if it was higher than 1, suppose 2, 2*6=12. Therefore it won't be a single digit.

The answer could also be 000. But it's unlikely.

Answer 2

QUESTION :- There is a three-digit number. The second digit is four times as big as the third digit, while the first digit is three less than the second digit. What is the number?

ANSWER :-

Since the number is a 3 digit number, number will be of the form $100 \times x + 10 \times y + z$.

Second digit is 4 times the third digit, $y = 4 \times z$

First digit is 3 less than the second digit, $x = y - 3$

Therefore, $x = 4×z - 3$

Since $x$ is a digit, it must lie between 1 and 9.

[NOTE :- $x$ cannot be 0 because if $x = 0$, then it is a two digit number.]

So, $z$ can take values 1 and 2.

[NOTE :- $z$ cannot be 3 because if $z = 3$, then $y$ will not be between 1 and 9.]

So, if $z = 1, x = 1$ and $y = 4$. Therefore, the number is 141.

If $z = 2, x = 5$ and $y = 8$. Therefore, the number is 582.

Therefore, the possible numbers are 141 and 582.