there is three traffic lights in different roads , they change in different times .frist one is in 48 second , second one is in 70 second and third one is in 108 second . if they change together in morning 7 O ' clock then when it will change again
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The traffic light at three different road crossing change after every 48 seconds,72 seconds and 108 seconds respectively.
So let us take the LCM of the given time that is 48 seconds, 72 seconds, 108 seconds
⇒ 48 = 2 × 2 × 2 × 2 × 3
⇒ 72 = 2 × 2 × 2 × 3 × 3
⇒ 108 = 2 × 2 × 3 × 3 × 3
Hence LCM of 48, 72 and 108 = (2 × 2 × 2 × 2 × 3 × 3 × 3)
LCM of 48, 72 and 108 = 432
So after 432 seconds they will change simultaneously
We know that
60 seconds = 1 minute
so on dividing 432 / 60 we get 7 as quotient and 12 as reminder
Hence, 432 seconds = 7 min 12 seconds
∴ The time = 7 a.m. + 7 minutes 12 seconds
Hence the lights change simultaneously at 7:07:12 a.m
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