Question

There is water to a height of 20cm in cylindrical glass jar of radius 7cm.in side the jar there is metal sphere of diameter of 7cm completely immersed,by what height the water will go down when the sphere is removed from the jar

Answer 1

Hey there!

Let h be the drop in the height of Water

Drop in Total volume Jar = Volume of Sphere

Volume of Cylinder= πr²h

π × 7² × h = (4/3) × π × 7³

h = 28/3 cm

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Answer 2

Answer:

7/6

Step-by-step explanation:

Volume of sphere = $\frac{4}{3} \pi r^3 =\frac{4}{3} \pi \times (\frac{7}{2})^3$

Volume of Cylinder= πr²h =  π(7)²h

Drop in Total volume Jar = Volume of Sphere

$\frac{4}{3} \pi \times (\frac{7}{2})^3=\pi (7)^2 h$

$\frac{4}{3}\times (\frac{7}{2})^3=(7)^2 h$

[tex]h=\frac{7}{6}/tex]

Hence the water will go down by 7/6 when the sphere is removed from the jar