Question

There resistances each of 10 are connected in series across 30 vots
battery current flowing through them will be:
1A
15A
30A
None
*​

Answer 1

Answer:

current is 1A

30 V /(10*3)

OR 30 V / 30 OHM =1 AMPERE. [I = P/R

Explanation:

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Answer 2

Answer:

Option 1) 1 A

The current in the circuit is of 1 A.

Explanation:

Resistors of 10 Ω are connected in series.

There are 3 resistors.

Battery of = 30 Volts is connected to the circuit

Current flowing in the circuit = ??

★ Find the equivalent resistance :

• R1 = 10 Ω
• R2 = 10 Ω
• R3 = 10 Ω

$\longrightarrow$ R1 + R2 + R3

$\longrightarrow$ 10 + 10 + 10

$\longrightarrow$ 30 Ω

★ Current in the circuit:

$\longrightarrow$ I = V/R

• V = 30 V
• R = 30 V

$\longrightarrow$ I = 30/30

$\longrightarrow$ I = 1 A

Current in the circuit = 1 A

Therefore, the current in the circuit is of 1 A.