Question

There was 156 ml of water in beaker A and B. After 40 ml of water was transferred from beaker B to beaker A, beaker B had twice as much as water as beaker A. How much was there in beaker A than beaker A at first?

Answer 1

Answer:

Beaker A = 12; Beaker B = 144 initially

Step-by-step explanation:

Let water in Beaker A be 'a' and that in beaker B be 'b';

Interpreting the given information;

a + b = 156 ---------> 1

2(a + 40) = b - 40

i.e. 2a + 80 = b - 40

i.e. 2a - b = -120 ------> 2

Adding both equations;

3a = 36 i.e. a = 12

b = 156 - 12 = 144

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Answer 2

Answer:

Beaker A = 12; Beaker B = 144 (initially)

Step-by-step explanation:

After 40 ml has been transferred then:  

Let water in Beaker A be 'a' and that in beaker B be 'b'

with 2a = b

Interpreting the given information;

a + b = 156 ml ---------> where as b = 2a (currently)

a + 2a = 156 ml

a = 156/3  

a = 52 ml (a currently)  

a - 40 ml = 12 ml (a initially) <------

156 ml - 12 ml = 144 ml (b initially) <-----

To verify;

a + b = 156

156 - 12 = b = 144 ml (b initially)

156 - 40 - 12 = 104

52 + 2(52) = 156 ml