Question

there was 60 ml of water in breaker A and 100 ml of water in breaker B find the ratio of the volume of water in a to the volume of water in breaker B after sometime water was added to both breaker breaker a had 90 ml of water the ratio of the volume of water in both breaker remain the same how much water was added to break b​

Answer 1

Answer:

The amount of water add to beaker B is 50 ml

Step-by-step explanation:

  Given water in beaker A = 60 ml

            water in beaker B= 100 ml

      ratio of volume of water in beaker A to the volume of water in beaker B

                           A : B = 60 : 100 = 6 : 10= 3 : 5

    after sometime some water is added to both beakers then

    beaker A had 90 ml of water and ratio of the volume of water in both beaker A and B are remains same

    let water in beaker B is 'b'

   ratio of volume of water in beaker A to volume water in beaker B =  90:b which is equals to 3 : 5

                           90 : b = 3 :5

  [ both are equal which means they are in proportion ]

        90 × 5 = b× 3 ⇒ $\frac{90 (5)}{3}$ =30 × 5= 150  

      water in beaker B is 150 ml

 the amount of water add to B = 150 -100 =50 ml