Question

There was a coconut farmer, he told his helper to arrange the harvest and count the no. of coconuts.
After a while the helper said
When I arrange it in 2 there is one coconut left.
When I arrange it in 3 there is one coconut left.
When I arrange it in 4 there is one coconut left.
When I arrange it in 5 there is one coconut left.
When I arrange it in 6 there is one coconut left.
When I arrange it in 7 there are no coconut left.

How many coconuts were there?



please don't give any wrong answers...​

Answer 1

Answer:301

Step-by-step explanation:

This is a case of lcm with remainders...

So we apply:-

lcm(2,3,4,5,6)m+1

(2×2×3×5)m+1

60m+1

where m is a number so chosen that 60m+1 will be divisible by 7.

We do this by trial and error:-

If m=1, 61, not divisible by 7

If m=2, 121, not divisible by 7

If m=3, 181, not divisible by 7

If m=4, 241, not divisible by 7

If m=5, 301, divisible by 7

So 301 is the answer

No doubt it is correct

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