Math, asked by venuNaidu1977, 1 year ago

There were 11 pigeons and 9 tigers. Ramesh counted legs of all these animals. How many legs were there altogether?
(A) 40
(B) 58
(C) 80
(D) none of these

Answers

Answered by yuvrajkj
2
the answer is (11 x 2) + (9 x 4) = 58

Harsha889: Tq fr following
yuvrajkj: welcome
Harsha889: hmm
Answered by Anonymous
0

bonjour dear!

here is your correct answer

first of all i remind you that pigeons have 2 legs and tigers - 4 legs


so in the question it is said that 11 pigeons and 9 tigers are there so, together

11*2+ 9*4

22+ 36= 58 legs



hope it helps

pls mark as brainliest answer

#be brainly

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